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<DIV><FONT face=Arial size=2>thanks ofr the clarification! </FONT></DIV>
<DIV><FONT face=Arial size=2>Daniel</FONT></DIV>
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<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black"><B>From:</B>
<A href="mailto:vanputte@nuc.net" title=vanputte@nuc.net>Ron Van Putte</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A href="mailto:discussion@nsrca.org"
title=discussion@nsrca.org>discussion@nsrca.org</A> </DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Friday, February 14, 2003 6:18
PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: Sharks tooth vs 1/2
cuban</DIV>
<DIV><BR></DIV>daniel dion wrote:<BR>
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<DIV><FONT face=Arial size=2>Is there someone to explain me the difference
between "Sharks tooth" and "1/2 cuban 8" please? I have no problem to
do the 1/2 cuban 8 or reverse cuban 8 but what's "Shark
tooth"???</FONT></DIV></BLOCKQUOTE>The Shark's Tooth is normally a turnaround
maneuver. It is entered upright, followed by a 90 degree pull to
vertical, followed by a rather long vertical climb. At the top of the
maneuver there is a 135 degree pull to a 45 degree downline, with a half roll
centered on the downline, and a 45 degree pull to upright flight.<BR><BR>It
was in the Master maneuver schedule in the 1999-2001 rule book and should be
in the rule book maneuver description section.<BR><BR>Ron Van
Putte<BR><BR></BLOCKQUOTE></BODY></HTML>