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<DIV><FONT size=2>Thanks again for all the great input. </FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=Arial size=2><B>-----Original Message-----</B><BR><B>From:
</B>george kennie <<A
href="mailto:geobet@gis.net">geobet@gis.net</A>><BR><B>To: </B><A
href="mailto:discussion@nsrca.org">discussion@nsrca.org</A> <<A
href="mailto:discussion@nsrca.org">discussion@nsrca.org</A>><BR><B>Date:
</B>Thursday, March 27, 2003 12:57 PM<BR><B>Subject: </B>Re: Center of
loop<BR><BR></DIV>
<BLOCKQUOTE dir=ltr
style="PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px"></FONT>Initially
I was ready to debate this one, as I saw the length of the 45 Degree up, to
one side of the vertical up, as being equal in length to the diameter of the
loop on the opposite side of the vertical up and therefore the vertical up
should represent the center, but there are a couple of other elements to
consider. Remember, we are required to execute an entry and exit line of equal
length. The end of the exit line would therefore be much closer to the
vertical up than the beginning of the entry line.If you take these two lines
into account, as indeed we must, you will then see that this shifts the center
location toward the 45 up and indeed Mr. Kababjian is correct, in my opinion,
that the center of the 45 up should represent the center of the maneuver.
<BR> Thanks Don for the stimulation. <BR>Georgie
<P>Rcmaster199@aol.com wrote:
<BLOCKQUOTE TYPE="CITE"><FONT face=Arial><FONT size=-1>In a message dated
3/20/2003 9:09:28 PM Eastern Standard Time, dszczur@maranatha.net
writes:</FONT></FONT> <BR> <BR>
<BLOCKQUOTE
style="PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #0000ff 2px solid; MARGIN-RIGHT: 0px"
TYPE="CITE"><FONT face=Arial><FONT size=-1>Subj:<B>Center of
loop</B></FONT></FONT> <BR><FONT face=Arial><FONT size=-1>Date:3/20/2003
9:09:28 PM Eastern Standard Time</FONT></FONT> <BR><FONT face=Arial><FONT
size=-1>From:<A
href="mailto:dszczur@maranatha.net">dszczur@maranatha.net</A></FONT></FONT>
<BR><FONT face=Arial><FONT size=-1>Reply-to:<A
href="mailto:discussion@nsrca.org">discussion@nsrca.org</A></FONT></FONT>
<BR><FONT face=Arial><FONT size=-1>To:<A
href="mailto:discussion@nsrca.org">discussion@nsrca.org</A></FONT></FONT>
<BR><I><FONT face=Arial><FONT size=-1>Sent from the
Internet</FONT></FONT></I> <BR> <BR>
<P><FONT face=Arial><FONT size=-1>Center maneuver, pull 45 degrees, 7/8
outside loop to verical, two point</FONT></FONT> <BR><FONT
face=Arial><FONT size=-1>roll up, exit upright.</FONT></FONT>
<P><FONT face=Arial><FONT size=-1>Where is the center? P03 Aresti
sequence shows center is the loop center,</FONT></FONT> <BR><FONT
face=Arial><FONT size=-1>IAC/full scale says center is the middle of the
45 degree line. By pattern</FONT></FONT> <BR><FONT face=Arial><FONT
size=-1>definition, the center of whole maneuver is maybe the
vertical up line-</FONT></FONT> <BR><FONT face=Arial><FONT size=-1>which
is it?</FONT></FONT>
<P><FONT face=Arial><FONT size=-1>Thanks,</FONT></FONT> <BR><FONT
face=Arial><FONT size=-1>Don</FONT></FONT></P></BLOCKQUOTE><FONT
face=Arial><FONT size=-1>Don,</FONT></FONT>
<P><FONT face=Arial><FONT size=-1>There are several elements but only three
parts, the 45 deg up line, the 7/8 loop, and the vert w/ 2 pt roll to
upright. I believe the IAC/full scale is correct= the middle of the 45 deg
up line.</FONT></FONT>
<P><FONT face=Arial><FONT size=-1>Matt
Kebabjian</FONT></FONT></P></BLOCKQUOTE></BLOCKQUOTE></BODY></HTML>