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<DIV><SPAN class=331373014-17112004><FONT face=Arial color=#0000ff size=2>And
now, the Dave and Dean show have spoken ...</FONT></SPAN></DIV>
<DIV> </DIV>
<P><FONT face="Times New Roman">Dean Pappas</FONT> <BR><FONT
face="Times New Roman">Sr. Design Engineer</FONT> <BR><FONT
face="Times New Roman">Kodeos Communications</FONT> <BR><FONT
face="Times New Roman">111 Corporate Blvd.</FONT> <BR><FONT
face="Times New Roman">South Plainfield, N.J. 07080</FONT> <BR><FONT
face="Times New Roman">(908) 222-7817 phone</FONT> <BR><FONT
face="Times New Roman">(908) 222-2392 fax</FONT> <BR><FONT
face="Times New Roman">d.pappas@kodeos.com</FONT> </P>
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<DIV class=OutlookMessageHeader dir=ltr align=left><FONT face=Tahoma
size=2>-----Original Message-----<BR><B>From:</B> discussion-request@nsrca.org
[mailto:discussion-request@nsrca.org]<B>On Behalf Of
</B>DaveL322@comcast.net<BR><B>Sent:</B> Wednesday, November 17, 2004 9:22
AM<BR><B>To:</B> discussion@nsrca.org<BR><B>Subject:</B> RE: 3-bladed props
for OS160FX<BR><BR></FONT></DIV>
<DIV>...and a further variable....</DIV>
<DIV> </DIV>
<DIV>It is quite difficult to measure the pitch of the prop without knowing
the zero angle of attack of the airfoil used on the prop (which often changes
along the span of the prop). So the pitch reading from a pitch gauge is
really just a reference. For the most part, I've found that reducing the
pitch of an APC close to the root results in a fairly equal reduction along
the span of the prop (as measured on a Prather pitch gauge).</DIV>
<DIV> </DIV>
<DIV>Regards,</DIV>
<DIV><BR>Dave</DIV>
<DIV> </DIV>
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style="PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #1010ff 2px solid">--------------
Original message -------------- <BR>
<DIV> I guess if you want to maintain a true helical pitch, if you are
reducing the pitch then you will need to add some pitch back towards the
tips. Higher pitch props have more twist along the blade than lower pitch
props. So if you depitch at one point towards the root, then you end up with
a blade that effectively has washout. Correct? That may be good for our
purpose.</DIV>
<DIV> </DIV>
<DIV>Bob.</DIV>
<DIV><BR><BR><B><I>Dean Pappas <d.pappas@kodeos.com></I></B>
wrote:</DIV>
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<DIV><SPAN class=514511421-16112004><FONT face=Arial color=#0000ff
size=2>Claudio,</FONT></SPAN></DIV>
<DIV><SPAN class=514511421-16112004><FONT face=Arial color=#0000ff
size=2>Ideally you would twist the prop at several places to acheiv
helical pitch. In practice, this is entirely unnecessary. Twist once, as
close to the hub as practical, and that will work just fine. I see that
Dave L added more detail to the procedure.</FONT></SPAN></DIV>
<DIV><SPAN class=514511421-16112004><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=514511421-16112004><FONT face=Arial color=#0000ff
size=2>until later,</FONT></SPAN></DIV>
<DIV><FONT face="Times New Roman">Dean Pappas</FONT> <BR><FONT
face="Times New Roman">Sr. Design Engineer</FONT> <BR><FONT
face="Times New Roman">Kodeos Communications</FONT> <BR><FONT
face="Times New Roman">111 Corporate Blvd.</FONT> <BR><FONT
face="Times New Roman">South Plainfield, N.J. 07080</FONT> <BR><FONT
face="Times New Roman">(908) 222-7817 phone</FONT> <BR><FONT
face="Times New Roman">(908) 222-2392 fax</FONT> <BR><FONT
face="Times New Roman">d.pappas@kodeos.com</FONT> </DIV>
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