[F3A-Discussion] Clarifications on certain maneuvers in the P and F sequences

[trexlesh@msn.com]

Just a point of interest....the P-13 power point in the NSRCA judging shows the immediacy as  well.
Thanks for the verification, Derek.

Rex

Sent from my Verizon Wireless Phone

----- Reply message -----
From: "Derek Koopowitz" <derekkoopowitz at gmail.com>
To: <f3a-discussion at lists.f3a.us>
Subject: [F3A-Discussion] Clarifications on certain maneuvers in the P and F	sequences
Date: Tue, Apr 24, 2012 9:46 am
I've had several conversations with different people about maneuvers P-13.03 (Consecutive three 1/4 Rolls followed by consecutive three 1/4 rolls in the opposite direction), F-13.05 (Roll combination with consecutive 1/4 roll, two snap rolls opposite, 1/4 roll), F-13.09 (45 degree upline with consecutive four 1/8 rolls followed by 1 1/2 snap in opposite direction) and F-13.11 (Clown dance with 1/2 loop, inverted 2 1/2 turn spin and two 1/4 rolls down).

In P-13.03 - there is no pause between the end of the 1st three 1/4 rolls and the start of the second set of 1/4 rolls - the reversal must be immediate.  I think a lot of people are thinking of this maneuver as a 3 of 4 point roll followed by a 3 of 4 point roll opposite and thus want to put an extended line between the two sets of 3 of 4 point rolls.  Since these are three 1/4 rolls, there is no requirement to extend the line after the 3rd 1/4 roll to make it "symmetrical" and thus the roll reversal should start immediately after the plane finishes the third 1/4 roll.

F-13.05 - There is no pause after the 1st snap and the 2nd snap should happen immediately after the 1st one.
F-13.09 - This is just like P-13.03 in that the 1 1/2 snap roll must happen immediately after the four 1/8 rolls.  There is no line between the end of the fourth 1/8 roll and the snap roll.

F-13.11 - Since this maneuver contains 2 elements (the 1/2 loop and then the spin), the center of the maneuver should be exactly in the middle - in other words, the distance to the outermost radius of the 1/2 loop (from the middle) is the same as the distance to the start of the spin entry.  As an example, this would be identical to the placement of a double immelman on center - 1/2 the maneuver will be to the left of center and the other half of the maneuver will be to the right of center.

Comments/questions?
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